Class 10 Mathematics · Chapter 4 NotesQuadratic Equations
Class 10 Mathematics Quadratic Equations notes covering standard form, factorisation, completing the square, quadratic formula, discriminant and word problems.
Quadratic Equations is the fourth chapter of Class 10 Mathematics. It begins with the standard form ax² + bx + c = 0, where a, b and c are real numbers and a ≠ 0, and shows how such equations arise from everyday situations such as finding the dimensions of a hall or the speed of a train. The chapter explains how to recognise a quadratic equation, how to find its roots by factorisation, by completing the square and by the quadratic formula, and how the discriminant b² − 4ac decides whether the roots are two distinct real numbers, two equal real numbers, or not real. You will also learn to translate word problems into quadratic equations, solve them, and reject answers that do not fit the situation.
What you'll learn
1Identify a quadratic equation and write it in standard form ax² + bx + c = 0, a ≠ 0.
2Represent real-life situations mathematically as quadratic equations.
3Find the roots of a quadratic equation by splitting the middle term and factorising.
4Solve a quadratic equation by completing the square.
5Apply the quadratic formula x = (−b ± √(b² − 4ac)) / 2a to find roots.
6Use the discriminant b² − 4ac to describe the nature of the roots.
7Solve word problems on numbers, ages, areas, speeds and costs using quadratic equations.
Chapter at a glance
01Standard Form and Basic Concepts
02Solution by Factorisation Method
03Solution by Completing the Square
04Quadratic Formula and Applications
05Nature of Roots and Discriminant
06Word Problems and Real-Life Applications
Detailed chapter notes
01
Standard Form and Basic Concepts
A quadratic equation in the variable x is an equation of the form ax² + bx + c = 0, where a, b and c are real numbers and a ≠ 0. This is called the standard form. Any equation p(x) = 0, where p(x) is a polynomial of degree 2, is a quadratic equation. A real number α is a root of ax² + bx + c = 0 if aα² + bα + c = 0. The roots of the equation and the zeroes of the polynomial ax² + bx + c are the same. Since a quadratic polynomial has at most two zeroes, a quadratic equation can have at most two roots. Many equations look quadratic but are not, so simplify first and then check the degree.
Standard formax² + bx + c = 0, a ≠ 0
α is a root if aα² + bα + c = 0
A quadratic equation has at most two roots
02
Forming Quadratic Equations from Situations
Quadratic equations appear when we describe real situations in mathematical language. The usual method is to take the unknown quantity as x, use the given condition to build an equation, and then simplify it into standard form. For example, if the breadth of a hall is x metres and its length is one metre more than twice the breadth, the length is (2x + 1) metres. If the carpet area is 300 square metres, then (2x + 1)x = 300, which gives 2x² + x − 300 = 0. Similarly, problems on marbles, toys, ages and speeds can be converted into quadratic equations by writing each condition carefully.
Take the unknown quantity as x
Write the given condition as an equation
Simplify and bring all terms to one side to get ax² + bx + c = 0
03
Solution by Factorisation
If ax² + bx + c can be written as the product of two linear factors, then each factor can be equated to zero to find the roots. This is done by splitting the middle term: find two numbers whose product is ac and whose sum is b, then group the terms and take common factors. For example, 2x² − 5x + 3 = 2x² − 2x − 3x + 3 = (2x − 3)(x − 1), so 2x − 3 = 0 or x − 1 = 0, giving x = 3/2 and x = 1. When the two factors are the same, the equation has two equal roots, as in 3x² − 2√6x + 2 = 0, where both roots are √2/√3.
Split the middle term using product ac and sum b
Equate each linear factor to zero
Repeated factors give two equal roots
04
Solution by Completing the Square
Completing the square changes a quadratic equation into a perfect square plus a constant, which can then be solved by taking square roots. The idea is to write x² + bx as (x + b/2)² − (b/2)². This method works for every quadratic equation and is the reasoning behind the quadratic formula. It is especially useful when factorisation is not easy. The steps are: divide by a if a ≠ 1, shift the constant term to the right side, add the square of half the coefficient of x to both sides, write the left side as a perfect square, and then take the square root of both sides.
Write x² + bx as (x + b/2)² − (b/2)²
Add the square of half the coefficient of x to both sides
Take square roots to get the two roots
05
Quadratic Formula and Its Use
The roots of ax² + bx + c = 0, when b² − 4ac ≥ 0, are given by the quadratic formula x = (−b ± √(b² − 4ac)) / 2a. To use it, first write the equation in standard form, note the values of a, b and c, and substitute them carefully. The formula comes from solving the general equation by completing the square, so it always gives the roots whenever real roots exist. It is very useful when the coefficients are large or when the equation does not factorise easily. After finding the roots, they can be checked by substituting them back into the original equation.
Identify a, b, c from the standard form before substituting
The formula works for every quadratic equation with real roots
06
Nature of Roots and the Discriminant
The expression b² − 4ac is called the discriminant of the quadratic equation ax² + bx + c = 0, because it decides the nature of the roots. If b² − 4ac > 0, the equation has two distinct real roots. If b² − 4ac = 0, the two roots are equal, and each root is −b/2a. If b² − 4ac < 0, there is no real number whose square is b² − 4ac, so the equation has no real roots. The discriminant is therefore a quick test that tells us whether real roots exist and whether they are equal or different, without solving the equation fully.
b² − 4ac > 0two distinct real roots
b² − 4ac = 0two equal real roots, each equal to −b/2a
b² − 4ac < 0no real roots
07
Word Problems and Real-Life Applications
Quadratic equations are used to solve many practical problems. The method is to read the problem, choose a variable for the unknown, form an equation from the given conditions, solve it, and then check which root makes sense in the situation. For example, if x is a length, breadth, age or speed, it cannot be negative, so a negative root is rejected. In the prayer hall problem, 2x² + x − 300 = 0 gives x = 12 or x = −12.5; since breadth cannot be negative, the breadth is 12 m and the length is 25 m. Problems on consecutive integers, areas, perimeters and production costs are solved in the same way.
Form the equation from the given condition
Solve by factorisation or the quadratic formula
Reject roots that do not fit the real situation
Want the complete chapter resources?Topic notes, quizzes and flashcards for Quadratic Equations.
Q1. What is the standard form of a quadratic equation? Give an example.
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Model answer
The standard form of a quadratic equation in the variable x is ax^2 + bx + c = 0, where a, b, c are real numbers and a ≠ 0. For example, 2x^2 + x - 300 = 0 is a quadratic equation in standard form.
Sample question3 marks
Q2. Find the roots of the quadratic equation 2x² – 5x + 3 = 0 by factorisation.
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Model answer
We split the middle term –5x as –2x –3x. So, 2x² – 5x + 3 = 2x² – 2x – 3x + 3 = 2x(x – 1) – 3(x – 1) = (2x – 3)(x – 1). Setting each factor to zero gives 2x – 3 = 0 or x – 1 = 0, so x = 3/2 or x = 1. Thus, the roots are 3/2 and 1.
Sample question3 marks
Q3. Solve the quadratic equation x^2 + 4x - 5 = 0 by the method of completing the square.
Q4. Find the roots of the quadratic equation 2x^2 - 4x + 3 = 0 using the quadratic formula. Also, determine the nature of its roots.
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Model answer
For 2x^2 - 4x + 3 = 0, a = 2, b = -4, c = 3. Discriminant = b^2 - 4ac = (-4)^2 - 4*2*3 = 16 - 24 = -8 < 0. Since discriminant is negative, the equation has no real roots.
Sample question3 marks
Q5. Find the discriminant of the quadratic equation 2x^2 - 4x + 3 = 0 and hence determine the nature of its roots.
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Model answer
For the equation 2x^2 - 4x + 3 = 0, a = 2, b = -4, c = 3. Discriminant D = b^2 - 4ac = (-4)^2 - 4*2*3 = 16 - 24 = -8. Since D < 0, the equation has no real roots.
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A quadratic equation in the variable x is an equation of the form ax² + bx + c = 0, where a, b and c are real numbers and a ≠ 0. Any equation p(x) = 0, where p(x) is a polynomial of degree 2, is a quadratic equation. Its standard form is ax² + bx + c = 0.
What is the discriminant of a quadratic equation?
The discriminant of ax² + bx + c = 0 is the expression b² − 4ac. It tells us the nature of the roots: two distinct real roots if b² − 4ac > 0, two equal real roots if b² − 4ac = 0, and no real roots if b² − 4ac < 0.
How do you know whether a quadratic equation has real roots?
Find the discriminant b² − 4ac. If it is greater than or equal to zero, the equation has real roots. If it is greater than zero, the roots are distinct; if it is equal to zero, the roots are equal. If it is less than zero, there are no real roots.
What is the quadratic formula?
The roots of ax² + bx + c = 0 are given by x = (−b ± √(b² − 4ac)) / 2a, provided b² − 4ac ≥ 0. Write the equation in standard form, identify a, b and c, and substitute them into the formula.
Why do we reject a negative root in word problems?
In many word problems the variable stands for a quantity such as length, breadth, age, speed or number of articles, which cannot be negative. So a negative root does not make sense in that situation and is rejected, even though it may satisfy the equation.
What is the difference between the roots of a quadratic equation and the zeroes of a quadratic polynomial?
There is no difference. A real number α is a root of ax² + bx + c = 0 if aα² + bα + c = 0, and α is also a zero of the polynomial ax² + bx + c. The zeroes of the polynomial and the roots of the corresponding equation are the same.