Class 11 Physics · Chapter 3 NotesMotion in a Plane
Class 11 Physics notes on Motion in a Plane: scalars and vectors, vector addition, projectile motion and uniform circular motion explained with key formulas.
Motion in a Plane extends the ideas of position, displacement, velocity and acceleration from straight-line motion to motion in two dimensions. In one dimension, direction is handled by plus and minus signs, but in a plane we need vectors. This chapter introduces scalars and vectors, the rules for adding, subtracting and multiplying vectors, and the resolution of a vector into components. Using these tools, you will describe motion in a plane with constant acceleration, analyse projectile motion as two independent one-dimensional motions, and study uniform circular motion, where speed is constant but the direction of velocity keeps changing, producing a centripetal acceleration directed towards the centre of the circle. The concepts developed here also extend naturally to three dimensions.
What you'll learn
1Distinguish between scalar and vector quantities with suitable examples
2Represent position and displacement vectors and check equality of vectors
3Add and subtract vectors using the triangle and parallelogram laws
4Resolve a vector into rectangular components using unit vectors i, j and k
5Add vectors analytically using their components
6Apply the kinematic equations for motion in a plane with constant acceleration
7Analyse projectile motion to find time of flight, maximum height and range
8Describe uniform circular motion and calculate centripetal acceleration
Chapter at a glance
01Scalars and Vectors in Two Dimensions
02Position, Velocity, and Acceleration Vectors
03Uniform Circular Motion and Related Concepts
Detailed chapter notes
01
Scalars and Vectors
A scalar quantity has magnitude only and is completely specified by a number with its proper unit, such as distance, mass, temperature and time. Scalars combine by ordinary algebra. A vector quantity has both magnitude and direction and obeys the triangle law or parallelogram law of addition; displacement, velocity, acceleration and force are vectors. A vector is written in bold face, such as A, and its magnitude, called its absolute value, is written as |A| or simply A. Two vectors are equal only if they have the same magnitude and the same direction; shifting a vector parallel to itself does not change it.
Scalarmagnitude only, e.g. distance, mass, temperature, time
Vectormagnitude and direction, e.g. displacement, velocity, acceleration, force
A = B only if |A| = |B| and their directions are the same
02
Position and Displacement Vectors
To locate an object moving in a plane, we choose an origin O. The position vector r of a point P is the vector OP, and in component form r = x i + y j, where x and y are the coordinates of the object. If the object moves from P at time t to P′ at time t′, the displacement vector is Δr = r′ − r, directed from P to P′. In components, Δr = Δx i + Δy j, where Δx = x′ − x and Δy = y′ − y. The displacement depends only on the initial and final positions, not on the actual path followed, so its magnitude is either less than or equal to the path length.
Position vectorr = x i + y j
DisplacementΔr = r′ − r = Δx i + Δy j
Magnitude of displacement ≤ path length
03
Multiplication of a Vector by a Real Number and the Null Vector
Multiplying a vector A by a positive number λ gives a vector λA whose magnitude is λ times |A| and whose direction is the same as that of A. If λ is negative, the direction of λA is opposite to that of A. If the scalar has its own physical dimension, the dimension of λA is the product of the dimensions of λ and A; for example, multiplying a velocity vector by a time interval gives a displacement vector. Adding a vector to its negative gives the null vector 0, whose magnitude is zero and whose direction cannot be specified. Also, A + 0 = A, λ0 = 0 and 0A = 0.
|λA| = λ|A| for λ > 0; direction reverses for λ < 0
A + (−A) = 0, the null vector with |0| = 0
A + 0 = A, λ0 = 0, 0A = 0
04
Addition and Subtraction of Vectors — Graphical Method
In the head-to-tail (triangle) method, vector B is placed with its tail at the head of A, and the vector drawn from the tail of A to the head of B gives the resultant R = A + B. In the parallelogram method, A and B are drawn from a common origin and the diagonal of the completed parallelogram gives the resultant; the two methods are equivalent. Vector addition is commutative, A + B = B + A, and associative, (A + B) + C = A + (B + C). Subtraction is defined as A − B = A + (−B), where −B has the same magnitude as B but the opposite direction.
Triangle lawplace vectors head to tail; resultant joins first tail to last head
Parallelogram lawresultant is the diagonal from the common origin
A + B = B + A; (A + B) + C = A + (B + C)
A − B = A + (−B)
05
Resolution of Vectors and Unit Vectors
Any vector A in a plane can be expressed as the sum of two component vectors along two non-collinear directions a and b: A = λa + μb, where λ and μ are real numbers. It is most convenient to resolve a vector along the axes of a rectangular coordinate system using unit vectors. A unit vector has magnitude 1 and no dimension or unit; i, j and k point along the x-, y- and z-axes. A vector A in the x-y plane is written as A = Ax i + Ay j, where Ax = A cos θ and Ay = A sin θ if A makes an angle θ with the x-axis. Conversely, A = √(Ax² + Ay²) and tan θ = Ay/Ax. A component can be positive, negative or zero depending on θ.
A = Ax i + Ay j, with Ax = A cos θ and Ay = A sin θ
A = √(Ax² + Ay²), θ = tan⁻¹(Ay/Ax)
Unit vectors i, j, k have magnitude 1 and give direction only
06
Vector Addition — Analytical Method
Graphical addition is useful for visualising vectors but can be tedious and limited in accuracy. In the analytical method, vectors are added by combining their components. If A = Ax i + Ay j and B = Bx i + By j, then R = A + B = Rx i + Ry j, where Rx = Ax + Bx and Ry = Ay + By. Each component of the resultant is the sum of the corresponding components of the vectors being added. The same idea extends to three dimensions and to the addition or subtraction of any number of vectors; for example, if T = a + b − c, then Tx = ax + bx − cx, and similarly for the y and z components.
R = A + B gives Rx = Ax + Bx and Ry = Ay + By
Extends to three dimensionsRz = Az + Bz
For T = a + b − cTx = ax + bx − cx, and similarly for y and z
07
Motion in a Plane with Constant Acceleration
For an object moving in a plane with constant acceleration a, the velocity and position at time t are given by v = v₀ + at and r = r₀ + v₀t + ½at², where v₀ and r₀ are the velocity and position at t = 0. In component form, vx = vox + ax t, vy = voy + ay t, x = x₀ + vox t + ½ax t² and y = y₀ + voy t + ½ay t². This shows that motion in a plane can be treated as two separate simultaneous one-dimensional motions with constant acceleration along two perpendicular directions. The choice of perpendicular directions is convenient in many physical situations, such as projectile motion.
v = v₀ + at and r = r₀ + v₀t + ½at²
x = x₀ + vox t + ½ax t²; y = y₀ + voy t + ½ay t²
Motion in a plane = two independent one-dimensional motions
08
Projectile Motion
An object in flight after being thrown or projected is called a projectile. Neglecting air resistance, its acceleration is that due to gravity, directed vertically downward, so ax = 0 and ay = −g. If it is projected with speed v₀ at angle θ₀ to the x-axis from the origin, then x = (v₀ cos θ₀)t and y = (v₀ sin θ₀)t − ½gt², while vx = v₀ cos θ₀ and vy = v₀ sin θ₀ − gt. The horizontal component of velocity stays constant and the vertical component changes like free fall. Eliminating t gives the path y = (tan θ₀)x − gx²/(2(v₀ cos θ₀)²), which is a parabola. The time to reach maximum height is tm = v₀ sin θ₀/g, the maximum height is hm = (v₀ sin θ₀)²/(2g), the time of flight is Tf = 2v₀ sin θ₀/g, and the horizontal range is R = v₀² sin 2θ₀/g, which is maximum when θ₀ = 45°.
x = (v₀ cos θ₀)t; y = (v₀ sin θ₀)t − ½gt²
Path is a parabolay = (tan θ₀)x − gx²/(2(v₀ cos θ₀)²)
Maximum height hm = (v₀ sin θ₀)²/(2g)
Time of flight Tf = 2v₀ sin θ₀/g
Range R = v₀² sin 2θ₀/g, maximum at θ₀ = 45°
09
Uniform Circular Motion
When an object moves along a circular path at constant speed, its motion is called uniform circular motion. Although the speed is constant, the direction of velocity changes continuously, so the object accelerates. The velocity at any point is along the tangent to the circle, and the acceleration is directed towards the centre, which is why it is called centripetal acceleration. Its magnitude is ac = v²/R, where v is the speed and R is the radius. Angular speed ω is the time rate of change of angular displacement, and v = ωR, so ac = ω²R. If T is the time period and ν the frequency, then ω = 2πν, v = 2πνR and ac = 4π²ν²R. The magnitude of the centripetal acceleration is constant, but its direction changes, so it is not a constant vector.
Velocity is tangential; acceleration is directed towards the centre
ac = v²/R = ω²R
v = ωR; ω = 2πν; v = 2πνR; ac = 4π²ν²R
Centripetal acceleration is not a constant vector
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Temperature has only magnitude and no direction, making it a scalar quantity. Displacement, velocity, and acceleration all require both magnitude and direction.
Question 02
A particle moves in a plane. Its position vector is given by r = (3t)i + (4t)j meters. What is the magnitude of the position vector at t = 1 second?
A5 m
B7 m
C12 m
D25 m
Show answer
Answer: (A) 5 m
At t = 1 s, r = 3i + 4j. Magnitude = √(3² + 4²) = √(9 + 16) = √25 = 5 m.
Question 03
In projectile motion, what is the acceleration in the horizontal direction?
AZero
Bg (acceleration due to gravity)
CConstant and non-zero
DIncreases with time
Show answer
Answer: (A) Zero
In projectile motion, there is no force acting horizontally (ignoring air resistance), so horizontal acceleration is zero. Only gravity acts vertically.
Question 04
What is the SI unit of angular velocity?
Arad/s
Bm/s
Crev/s
DHz
Show answer
Answer: (A) rad/s
Angular velocity is the rate of change of angular displacement and its SI unit is radian per second (rad/s).
Question 05
A vector has components Ax = 3 m and Ay = 4 m. What is the magnitude of this vector?
A5 m
B7 m
C1 m
D12 m
Show answer
Answer: (A) 5 m
The magnitude is calculated using A = √(Ax² + Ay²) = √(3² + 4²) = √(9 + 16) = √25 = 5 m.
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Q1. Distinguish between position and displacement vectors in a plane. Why is displacement considered path-independent according to the NCERT text?
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Model answer
A position vector (r) describes the location of an object relative to a chosen origin (O) at a specific time; it is represented by a straight line from the origin to the point P. A displacement vector is the straight line joining the initial position (P) and the final position (P') of an object. Displacement is path-independent because it depends only on the initial and final coordinates, not on the actual course taken by the object. Consequently, the magnitude of displacement is either less than or equal to the actual path length.
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Q2. Explain the concept of instantaneous velocity for an object moving in a plane. How is its direction determined at any point on its path?
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Model answer
Instantaneous velocity is defined as the limiting value of the average velocity as the time interval approaches zero, expressed as v = dr/dt. Graphically, as the time interval delta-t decreases, the displacement vector delta-r becomes smaller and its direction approaches the tangent to the path. Therefore, the direction of velocity at any point on the path of an object is always tangential to the path at that point and points in the direction of motion.
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Q3. Explain the principle of independence of horizontal and vertical components of motion in a projectile, as stated by Galileo.
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Model answer
According to Galileo, the motion of a projectile is the result of two separate, simultaneously occurring components of motion that do not affect each other. One component is along the horizontal direction, which moves with constant velocity as there is no horizontal acceleration. The other component is along the vertical direction, which experiences a constant acceleration due to gravity (g) directed downwards. These two perpendicular components act independently to determine the parabolic trajectory of the object.
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Q4. Explain why an object moving in a uniform circular motion is said to be accelerating even though its speed remains constant. Define the direction of this acceleration.
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Model answer
In uniform circular motion, an object moves along a circular path at a constant speed. However, velocity is a vector quantity, and since the direction of motion changes continuously at every point along the circle, the velocity is not constant. Any change in velocity over time constitutes acceleration. This acceleration is called centripetal acceleration. According to the NCERT text, its direction is always perpendicular to the velocity and points towards the centre of the circular path at every instant.
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Q5. Define a null vector. Explain its physical significance using the example of displacement and state two of its algebraic properties.
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Model answer
A null or zero vector (0) is a vector with zero magnitude and an unspecified direction. Physically, it represents situations where the net result of vector quantities is zero; for example, if an object moves from point P to P' and then returns to P, its total displacement is a null vector because the initial and final positions coincide. Two properties are: (1) Adding a null vector to any vector A results in the same vector A (A + 0 = A). (2) Multiplying any vector A by the number zero results in a null vector (0A = 0).
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What is the difference between a scalar and a vector quantity?
A scalar quantity has magnitude only and is completely specified by a number with its unit, such as distance, mass, temperature or time. A vector quantity has both magnitude and direction and obeys the triangle or parallelogram law of addition, such as displacement, velocity, acceleration or force.
What is a null vector or zero vector?
A null vector is a vector with zero magnitude. Since its magnitude is zero, its direction cannot be specified. It results when a vector is added to its negative, as in A + (−A) = 0, or when a vector is multiplied by zero. It satisfies A + 0 = A, λ0 = 0 and 0A = 0.
Why is the path of a projectile a parabola?
For a projectile launched from the origin with speed v₀ at angle θ₀, x = (v₀ cos θ₀)t and y = (v₀ sin θ₀)t − ½gt². Eliminating t gives y = (tan θ₀)x − gx²/(2(v₀ cos θ₀)²), which is of the form y = ax + bx², the equation of a parabola.
What is the maximum horizontal range of a projectile?
The horizontal range is R = v₀² sin 2θ₀/g. For a given projection speed v₀, R is maximum when sin 2θ₀ is maximum, that is when θ₀ = 45°. The maximum range is then Rm = v₀²/g.
Why is there acceleration in uniform circular motion even though the speed is constant?
In uniform circular motion the speed is constant, but the direction of velocity changes continuously. Since velocity is a vector, a change in direction is a change in velocity, so the object accelerates. This acceleration is directed towards the centre of the circle and has magnitude ac = v²/R.
How do you add two vectors analytically?
Write each vector in component form, for example A = Ax i + Ay j and B = Bx i + By j. The resultant is R = A + B = Rx i + Ry j, where Rx = Ax + Bx and Ry = Ay + By. The magnitude is R = √(Rx² + Ry²) and its direction is given by tan θ = Ry/Rx.