Class 11 Physics · Chapter 2 NotesMotion in a Straight Line
Revise Class 11 Physics Chapter 2 Motion in a Straight Line: displacement, speed, velocity, acceleration, kinematic equations, free fall and relative velocity.
Motion in a Straight Line is the first step into kinematics — the study of how objects move, without asking why they move. In this chapter you learn to describe motion along a straight line, called rectilinear motion, using position, path length, displacement, speed, velocity and acceleration. You will see how average values differ from instantaneous values, how position-time and velocity-time graphs tell the story of a journey, and how the area under a velocity-time graph gives displacement. For motion with constant acceleration, three simple kinematic equations connect displacement, time, initial velocity, final velocity and acceleration. The chapter also introduces relative velocity, showing that motion is always measured with respect to a chosen frame. These ideas are used later for motion in a plane, laws of motion and beyond.
What you'll learn
1Distinguish between position, path length and displacement for motion along a straight line
2Define average speed, average velocity, instantaneous speed and instantaneous velocity with their SI units
3Interpret position-time and velocity-time graphs, including slope and area
4Define average and instantaneous acceleration and identify their signs in different situations
5Apply the kinematic equations v = v₀ + at, x = v₀t + ½at² and v² = v₀² + 2ax to uniformly accelerated motion
6Analyse free fall as motion with uniform acceleration g and use Galileo's law of odd numbers
7Calculate relative velocity of one object with respect to another in one dimension
Chapter at a glance
01Position, Path Length, and Displacement
02Velocity and Speed: Average and Instantaneous
03Relative Velocity and Graphical Analysis
Detailed chapter notes
01
Position, Path Length and Displacement
To describe motion we first fix a reference point called the origin and choose a positive direction along the line of motion. The position of an object is its coordinate with respect to this origin; positions to the right are taken as positive and to the left as negative. The path length is the total distance actually covered, while displacement is the change in position, written as Δx = x₂ – x₁. Displacement has both magnitude and direction, so it can be positive, negative or zero, whereas path length is always positive. For motion along a straight line without any reversal, the magnitude of displacement equals the path length; if the object turns back, the path length becomes greater.
Displacement Δx = x₂ – x₁ (a vector quantity in one dimension, with sign)
Path length = total distance travelled (a scalar, always positive)
Magnitude of displacement ≤ path length
02
Average Velocity and Average Speed
Average velocity tells how fast position changes over a time interval. It is the displacement divided by the time interval, so it carries the sign of the displacement. Average speed is the total path length divided by the time interval and is always positive. Because path length is at least as large as the magnitude of displacement, average speed is greater than or equal to the magnitude of average velocity over any finite interval. The two become equal when the object moves in one direction without reversing. Both are measured in metres per second (m s⁻¹) in SI units.
Average velocity = Δx / Δt
Average speed = total path length / Δt
Average speed ≥ magnitude of average velocity
03
Instantaneous Velocity and Speed
Average velocity over a long interval hides how fast the object moved at each instant. To capture this, we shrink the time interval Δt to be infinitesimally small. The limiting value of Δx/Δt as Δt tends to zero is the instantaneous velocity, written v = dx/dt. On a position-time graph, this equals the slope of the tangent drawn at that instant. Instantaneous speed is simply the magnitude of instantaneous velocity, so a velocity of +24 m s⁻¹ and one of –24 m s⁻¹ both correspond to a speed of 24 m s⁻¹. For uniform motion, velocity is the same at every instant and equals the average velocity.
v = dx/dt (limit of Δx/Δt as Δt → 0)
Slope of the tangent to the x-t graph gives instantaneous velocity
Instantaneous speed = magnitude of instantaneous velocity
04
Acceleration: Average and Instantaneous
Velocity usually changes during motion, and the rate of change of velocity with time is called acceleration. Average acceleration over an interval is the change in velocity divided by the time interval, a = Δv/Δt. Instantaneous acceleration is the limit of this ratio as Δt tends to zero, a = dv/dt, and equals the slope of the tangent to the velocity-time graph. Acceleration may arise from a change in speed, a change in direction, or both. Its SI unit is m s⁻². A useful result is that the area under the velocity-time curve between two instants equals the displacement during that interval.
Average acceleration a = Δv/Δt
Instantaneous acceleration a = dv/dt
Area under the v-t curve = displacement
05
Kinematic Equations for Uniformly Accelerated Motion
When acceleration is constant, the average acceleration equals the constant value a, and simple relations connect the five quantities: displacement x, time t, initial velocity v₀, final velocity v and acceleration a. Starting from v = v₀ + at and using the area under the v-t graph, we obtain x = v₀t + ½at² and v² = v₀² + 2ax. These are the kinematic equations of rectilinear motion for constant acceleration. If the object starts at x₀ instead of the origin, x is replaced by (x – x₀). All quantities are algebraic, so signs must be substituted carefully.
v = v₀ + at
x = v₀t + ½at²
v² = v₀² + 2ax
If position at t = 0 is x₀, replace x by (x – x₀)
06
Free Fall and Galileo's Law of Odd Numbers
An object released near the Earth's surface, with air resistance neglected, is in free fall. It moves with a constant downward acceleration g, about 9.8 m s⁻². Taking upward as positive, a = –g, and the kinematic equations become v = –gt, y = –½gt² and v² = –2gy for an object released from rest at y = 0. Galileo showed that the distances covered in successive equal time intervals by a body falling from rest are in the ratio 1 : 3 : 5 : 7 : 9 : 11 …, known as the law of odd numbers. Free fall is therefore a standard example of uniformly accelerated motion.
g ≈ 9.8 m s⁻², directed downward
For free fall from restv = –gt, y = –½gt², v² = –2gy (upward positive)
Motion is always described with respect to a chosen frame of reference, so the velocity of an object depends on the observer. If two objects A and B move along the same straight line with velocities v_A and v_B, the velocity of A relative to B is v_AB = v_A – v_B, and the velocity of B relative to A is v_BA = v_B – v_A. When both move in the same direction, the relative velocity is the difference of speeds; when they move in opposite directions, it is the sum. This idea explains everyday situations such as two trains passing each other or a boat moving in a river.
v_AB = v_A – v_B
v_BA = –v_AB
Same directionsubtract speeds; opposite directions: add speeds
Want the complete chapter resources?Topic notes, quizzes and flashcards for Motion in a Straight Line.
A person walks 5 m north, then 3 m south. What is the displacement of the person?
A8 m north
B2 m north
C2 m south
D5 m north
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Answer: (B) 2 m north
Displacement is the straight-line distance from initial to final position. Net displacement = 5 m north - 3 m south = 2 m north.
Question 02
A car travels 100 m in 5 seconds. What is its average speed?
A20 m/s
B25 m/s
C15 m/s
D30 m/s
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Answer: (A) 20 m/s
Average speed = Total distance / Total time = 100 m / 5 s = 20 m/s. This is a direct application of the definition of average speed.
Question 03
If an object moves with uniform acceleration, what does this mean?
AThe velocity remains constant throughout the motion
BThe velocity changes by equal amounts in equal intervals of time
CThe object travels equal distances in equal time intervals
DThe object's speed increases then decreases periodically
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Answer: (B) The velocity changes by equal amounts in equal intervals of time
Uniform acceleration means the rate of change of velocity is constant, so velocity increases or decreases by the same amount in equal time intervals.
Question 04
If object A moves at 60 km/h and object B moves at 40 km/h in the same direction, what is the relative velocity of A with respect to B?
A20 km/h
B100 km/h
C40 km/h
D60 km/h
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Answer: (A) 20 km/h
Relative velocity in the same direction is the difference of velocities: v_AB = v_A - v_B = 60 - 40 = 20 km/h.
Question 05
Which of the following is a scalar quantity?
ADisplacement
BPath length
CVelocity
DAcceleration
Show answer
Answer: (B) Path length
Path length is the total distance traveled along the actual route and has only magnitude, making it a scalar. Displacement, velocity, and acceleration are vectors.
Ready for more practice?Unlock the full quiz for this chapter.
Q1. Distinguish between path length and displacement. Under what condition is the magnitude of displacement equal to the path length of an object?
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Model answer
Path length is the total distance traversed by an object during its motion and is a scalar quantity, meaning it only has magnitude. Displacement is the change in position of the object (final position minus initial position) and is a vector quantity, possessing both magnitude and direction. The magnitude of displacement is equal to the path length only when the object moves along a straight line in a single direction without turning back.
Sample question3 marks
Q2. Explain the physical significance of the sign of acceleration in rectilinear motion. Does a negative acceleration necessarily imply that the speed of an object is decreasing? Justify your answer using the example of an object in free fall.
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Model answer
The sign of acceleration depends on the chosen positive direction of the axis and does not independently indicate if an object is speeding up or slowing down. If acceleration and velocity have the same sign, the object speeds up; if they have opposite signs, it slows down. A negative acceleration does not always mean slowing down. For example, if the upward direction is positive, a falling object has negative acceleration due to gravity (-g). Since its velocity is also negative (downward), the object actually speeds up despite the negative acceleration.
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Q3. In the study of kinematics, when is it valid to treat an object as a 'point object'? Provide one example from the NCERT text where this approximation is applicable.
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Model answer
An object can be treated as a point object if its size is much smaller than the distance it moves within a reasonable duration of time. This approximation simplifies the description of motion by neglecting the internal structure or size of the object. For example, a railway carriage moving between two stations or the Earth revolving around the Sun can be considered point objects because the distances they travel are vast compared to their actual dimensions.
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Q4. Define 'stopping distance' of a vehicle and derive its mathematical expression in terms of initial velocity (v0) and acceleration (a). How is the stopping distance affected if the initial velocity of the vehicle is doubled?
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Model answer
Stopping distance is the distance a vehicle travels before coming to a rest after brakes are applied. Using the kinematic equation v^2 = v0^2 + 2ax, and setting final velocity v = 0, we get 0 = v0^2 + 2as (where s is stopping distance and a is negative acceleration/deceleration). This simplifies to s = -(v0^2) / 2a. The equation shows that stopping distance is proportional to the square of the initial velocity. Therefore, if the initial velocity is doubled, the stopping distance increases by a factor of four (2 squared = 4).
Want more questions with answers?Get the full practice set for this chapter.
What is the difference between distance and displacement?
Distance, or path length, is the total length actually covered and is always positive. Displacement is the change in position, Δx = x₂ – x₁, and can be positive, negative or zero. For motion without reversal along a straight line, the magnitude of displacement equals the distance travelled.
What is the difference between speed and velocity?
Speed is the rate of covering path length and has no direction, while velocity is the rate of change of position and carries a sign along the chosen axis. Average speed is always greater than or equal to the magnitude of average velocity; instantaneous speed equals the magnitude of instantaneous velocity.
What are the three kinematic equations for uniformly accelerated motion?
For constant acceleration a, with initial velocity v₀ and displacement x, the equations are v = v₀ + at, x = v₀t + ½at² and v² = v₀² + 2ax. They connect displacement, time, initial velocity, final velocity and acceleration, and all quantities must be substituted with proper signs.
Why is acceleration due to gravity negative in free fall?
The sign depends on the direction chosen as positive. If upward is taken as positive, the acceleration due to gravity points downward, so a = –g ≈ –9.8 m s⁻². This negative acceleration decreases the speed of an object thrown upward and increases the speed of a falling object.
How do you find velocity from a position-time graph?
The instantaneous velocity at any instant equals the slope of the tangent drawn to the position-time graph at that point. The average velocity over an interval equals the slope of the straight line joining the two points on the graph corresponding to the start and end of the interval.
What is relative velocity in one dimension?
Relative velocity is the velocity of one object measured with respect to another. For objects A and B on a straight line, v_AB = v_A – v_B. If they move in the same direction, the relative speed is the difference of their speeds; if in opposite directions, it is their sum.